remove debug line and output files name depends on the input file

outputDigitization.cc

@@ -361,8 +361,8 @@ void generateWaveform(string fileName, bool DRAW){
 		cout << fileName << " didn't open" << endl;
 		return;
 	}
-	TTree* eventDatatree = (TTree*)inFile->Get("EventData");
 
+	TTree* eventDatatree = (TTree*)inFile->Get("EventData");
 	TTree* tree = (TTree*)inFile->Get("RPD1tree");
 
 	vector<double> *Px=0, *Py=0, *Pz=0, *time=0, *LastStepZf = 0;
@@ -382,8 +382,7 @@ void generateWaveform(string fileName, bool DRAW){
 
 	//Output root file
 	double x=0, y=0,z=0, LastStepZ = 0;
-
-	TFile* outFile = new TFile( "output.root", "RECREATE");
+	TFile* outFile = new TFile( Form("WF_%s",fileName.c_str()),  "RECREATE");
 	TTree* outTree = new TTree( "tree", "tree" );
 	outTree->Branch("gunPosX",&x);
 	outTree->Branch("gunPosY",&y);
@@ -407,7 +406,6 @@ void generateWaveform(string fileName, bool DRAW){
 
 		int nEntries = tree->GetEntries();
 		for(int ev = 0; ev < nEntries; ev++){
-			if (ev > 10) break;
 			eventDatatree->GetEntry(ev);
 			tree->GetEntry(ev);
 			x=Xf ;